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Subsection A.2 Field Properties of the Real Numbers

We summarize the principles that define operations on the set of real numbers. Methods of performing calculations, simplifying algebraic expressions, and solving equations follow from these principles.
The Distributive Law, together with the other field properties, allows us to multiply polynomial.

Example A.2.17. Multiplying a Polynomial.

Multiply \((2x+1)(x^2-3x+5)\text{.}\)
Answer.
\(2x^3-5x^2+7x+5\)
Solution.
First we use the distributive law, multiplying each term in the second factor by \(2x+1\text{:}\) \((2x+1)(x^2-3x+5)=(2x+1)(x^2)+(2x+1)(-3x)+(2x+1)(5)\text{.}\)
An obtional step, but one that makes the distributive law more evident, is to us the commutative law of multiplication to reverse the order of the factors in each term: \((2x+1)(x^2)+(2x+1)(-3x)+(2x+1)(5)=x^2(2x+1)+(-3x)(2x+1)+5(2x+1).\)
We can then use the distributive law on each term to get \(x^2(2x+1)+(-3x)(2x+1)+5(2x+1)=x^2(2x)+x^2(1)-3x(2x)-3x(1)+5(2x)+5(1) 2x^3+x^2-6x^2-3x+10x+5 \)
Finally, we use the distributive law to combine like terms: \(2x^3+x^2-6x^2-3x+10x+5 =2x^3+(1-6)x^2+(10-3)x+5 =2x^3-5x^2+7x+5.\)
Although the distributive law makes the process work, we typically speed the process up by multiplying each term in the first factor by each term in the second factor: \((2x+1)(x^2-3x+5)=2x(x^2)+2x(-3x)+2x(5)+1(x^2)+1(-3x)+1(5) =2x^3-6x^2+10x+x^2-3x+5 =2x^3-5x^2+7x+5.\)
As demonstrated in the solution of Example A.2.17, the product of two polynomials can be found by multiplying each term in the first polynomial by each term in the second polynomial and then adding these products. If the first polynomial has \(m\) terms and the second polynomial has \(n\) terms, then there will be \(mn\) terms before we combine like terms.